26.4 REFRACTION AT SPHERICAL SURFACE
26.4.1 Formula for Refraction at Spherical Surface
1. Suppose a spherical surface SS' separates one transparent medium of refractive index n1 from another transparent medium of refractive index n2 where n2 > n1. A point object O is placed in the medium of refractive index n1 close to the surface, as shown in Figure 26.20(a).
2. When light from O reaches the surface, it will refract at the curved surface as it enters the second medium. After that, if the light is allowed to converge to a point, a real point image I will be formed.
3. On the other hand, if the light diverges after entering the second medium, a virtual point image will be formed, as shown in Figure 26.20(b), (c).
4. The spherical surface has radius of curvature r. The point object is placed at distance u from the surface. An image is formed at distance v from the surface. Then u, v and r are related to one another by the following formula:
$\boxed{\frac{n_1}{u}+\frac{n_2}{v}=\frac{|n_2-n_1|}{r}}$
where $|n_2 − n_1|$ is a positive value.
Derivation:
Refer to Figure 26.21.
Using ΔOAC,
Using ΔCAI,
$i = \alpha + \gamma$ ...(1)
$\gamma = r + \beta$
$r = \gamma − \beta$ ...(2)
At A,
$\boxed{n_1 \ sin \ i = n_2 \ sin \ r}$ ...(3)
If A is close to the axis of the curved surface then i and r are very small. We can assume
$sin / r ≅ r$
where i and r are in radian.
Expression (3) becomes
$n_2i = n_2 r$
Using (1) and (2),
$n_1(\alpha + \gamma) = n_2(\gamma − \beta)$
Rearranging,
$n_1\alpha + n_2\beta = (n_2 − n_1)\gamma$ ...(4)
$tan \ \alpha ≅ \alpha = \frac{AQ}{OQ}$, $tan \ \beta ≅ \beta = \frac{AQ}{IQ}$, $tan \ \gamma ≅ \gamma = \frac{AQ}{CQ}$
since i and r are small, and so α, β and γ are also small.
From (4),
$\left(\frac{n_1AQ }{OQ}\right) + \left(\frac{n_2AQ}{IQ}\right) = \frac{(n_2 − n_1)AQ}{CQ}$
But, $OQ ≅ OP = u$, $IQ ≅ IP = v$, $CQ ≅ CP = r$
We get
$\boxed{\frac{n_1}{u} + \frac{n_2}{v} = \frac{n_2-n_1}{r}}$
26.4.2 Sign Convention
(a) For u and v
We adopt the sign convention of ‘real is positive’.
If the object and image are real, then the object distance u and image distance v are positive.
(b) For r
Refer to Figure 26.22(a). The centre of curvature C of the surface is inside the medium whose refractive index is n2 where n2 > n1. Then r is positive.
Refer to Figure 26.22(b). C is inside the medium with n2 where n2 < n1. Then r is negative.
EXAMPLE 26.8
Refer to Figure 26.22(a), n1 = 1.0 and n2 = 1.52. The radius of curvature of the spherical surface is 5.0 cm. A point object is placed (a) 50 cm (b) 5 cm from the surface and inside the medium with refractive index n1. Determine the distance of the image formed.
Answer
(a)
$\frac{n_1}{u} + \frac{n_2}{v} = \frac{n_2-n_1}{r}$
$\frac{1}{+50} + \frac{1.52}{v} = \frac{1.52-1.0}{+5.0}$
$v = +18.1 \ cm$ (real image)
The real image is formed at a distance of 18.1 cm from the spherical surface and inside the medium with n2. The object and image are on opposite sides of the surface.
(b)
$\frac{1}{+5} + \frac{1.52}{v} = \frac{1.52-1.0}{+5.0}$
$v = −15.8 \ cm$ (virtual image)
The virtual image is formed at a distance of 15.8 cm from the spherical surface and inside the medium with n1. The object and image are in the same medium.
EXAMPLE 26.9
Refer to Figure 26.23. A point object O is placed 10 cm in front of a spherical surface SS' with radius of curvature 10 cm. Determine the image distance.
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Answer
Since the object is in an optically denser medium (n1 > n2), u = +10 cm and C is inside an optically less dense median, we have r = −10 cm.
$\frac{n_1}{u} + \frac{n_2}{v} = \frac{|n_2-n_1|}{r}$
$\frac{1.5}{+10} + \frac{1}{v} = \frac{|1.0-1.5|}{-10}$
$v = −5.0 \ cm$ (virtual image)
The virtual image is formed at a distance of 5.0 cm from the spherical surface and inside the medium with n1. The object and image are in the same medium.
Applications of Refraction at a Spherical Surface
Understanding how curved surfaces bend light and form images in real-life technology
🔍 Introduction
Refraction at a spherical surface is an important concept in optics. It explains how light bends when passing between two media with different refractive indices through a curved boundary. This principle is widely applied in many optical devices and everyday situations.
👓 Lenses (Convex & Concave)
Lenses are made from spherical surfaces that refract light to form images.
- Convex lenses focus light to form real images (used in cameras, microscopes).
- Concave lenses spread light (used in glasses for myopia).
📷 Optical Instruments
Many devices rely on spherical refraction to function properly:
- Microscopes magnify tiny objects
- Telescopes observe distant objects
- Cameras capture focused images
👁️ Human Eye
The human eye uses spherical refraction naturally.
- The cornea and lens bend light
- Images are formed on the retina
- Vision defects occur due to improper refraction
💧 Water & Glass Effects
Everyday examples of spherical refraction include:
- Objects in water appear bent or shifted
- Fish bowls distort or magnify images
🔌 Optical Fiber
Refraction occurs when light enters and exits optical fibers, enabling data transmission in communication systems.
✨ Conclusion: Refraction at a Spherical Surface
Refraction at a spherical surface is a fundamental concept in optics that explains how light bends when passing between different media through a curved boundary. This principle is essential for understanding image formation in lenses, optical instruments, and even the human eye.
By applying the formula n₁/u + n₂/v = (n₂ − n₁)/r, we can accurately determine the position and nature of images formed by spherical surfaces. This makes it a key concept in physics education, optical engineering, and real-world technology.
From cameras and microscopes to vision correction and fiber optics, refraction at spherical surfaces plays a crucial role in modern science and daily life. Mastering this concept not only improves problem-solving skills but also provides deeper insight into how light behaves in practical applications.
❓ Frequently Asked Questions (FAQ)
Refraction at a spherical surface is the bending of light when it passes between two media with different refractive indices through a curved boundary. This process determines how images are formed.
The formula is: n₁/u + n₂/v = (n₂ − n₁)/r, where u is object distance, v is image distance, and r is the radius of curvature.
A real image is formed when light rays actually converge, while a virtual image is formed when rays appear to diverge from a point.
The sign convention helps determine whether distances and radius are positive or negative. Typically, real objects/images are positive, and the sign of r depends on the position of the center of curvature.
It is used in lenses, cameras, microscopes, telescopes, eyeglasses, and the human eye to form and control images.




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